Math help

daledude wrote:

Tyreaus Dreacon wrote: Lemme guess, you all got greek letters?

No just the sigma, which I believe you are already familiar with. And then next to the sigma is something like (2/7)^n. Usually they go from n=1 or 0 to infinity. We deal mostly with the question of whether or not series converge. That is, if you add all the terms (an infinite amount) do you get a number or +/-infinity.

Yeah that’s in one of the questions I just can’t draw that out on here. xD But yes we do see that as well. We just did that converging infinite series and how to add sums of infinite series as well.

I have an idea for 14...

5x 2/x 4=x 4/x-2 because both sides of that equation = r. Solve for x.

I’m determined to live forever, or die trying. - Yossarian

daledude wrote: I have an idea for 14...

5x+2/x+4=x+4/x-2 because both sides of that equation = r. Solve for x.

(5x+2)(x-2)=1
5x^2-8x-5=0
That’s just a quadratic and I’ll bet the roots are 1 and 3

Oh for crap sakes yeah...you’re probably right...lol
I didn’t even think of making them equal like that. xD

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote: Lemme guess, you all got greek letters?

No just the sigma, which I believe you are already familiar with. And then next to the sigma is something like (2/7)^n. Usually they go from n=1 or 0 to infinity. We deal mostly with the question of whether or not series converge. That is, if you add all the terms (an infinite amount) do you get a number or +/-infinity.

Yeah that’s in one of the questions I just can’t draw that out on here. xD But yes we do see that as well. We just did that converging infinite series and how to add sums of infinite series as well.

Yeah, it only works for geometric series though which is why they’re our favorite. Right now we’re using infinite series to approximate values of non-elementary integrals.

I’m determined to live forever, or die trying. - Yossarian

Tyreaus Dreacon wrote:

daledude wrote: I have an idea for 14...

5x+2/x+4=x+4/x-2 because both sides of that equation = r. Solve for x.

(5x+2)(x-2)=1
5x^2-8x-5=0
That’s just a quadratic and I’ll bet the roots are 1 and 3

Oh for crap sakes yeah...you’re probably right...lol
I didn’t even think of making them equal like that. xD

lol, yeah with geometric series it’s all about the r.

I’m determined to live forever, or die trying. - Yossarian

I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

I’m determined to live forever, or die trying. - Yossarian

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I’m determined to live forever, or die trying. - Yossarian

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I ended up getting 10^1/2 / 2 as R which gave me D as well.

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I ended up getting 10^1/2 / 2 as R which gave me D as well.

You can always check by multiplying 8 by r^2. If that works it has to be right.

I’m determined to live forever, or die trying. - Yossarian

I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I’m determined to live forever, or die trying. - Yossarian

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I ended up getting 10^1/2 / 2 as R which gave me D as well.

You can always check by multiplying 8 by r^2. If that works it has to be right.

I figured R^2 to be 20/8 (before simplifying to 10/4) so...

daledude wrote: I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I thought it was (x+4)^2 = (5x+2)(x-2) is what I got...

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I ended up getting 10^1/2 / 2 as R which gave me D as well.

You can always check by multiplying 8 by r^2. If that works it has to be right.

I figured R^2 to be 20/8 (before simplifying to 10/4) so...

It’s just to check if you made an algebra mistake. It looks to me like it has to be D though.

I’m determined to live forever, or die trying. - Yossarian

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I got 33...

sqrt=square root

r= sqrt(20/8)
simplifies to sqrt(2*10/4*2)
two’s cancel. the four comes out as a 1/2
r=(1/2)sqrt(10)
8*r=answer D

It says the answer is B.

And, for some reason, I’m totally lost for the one you explained. x.x

It could be an algebra error on my part...

It’s really just moving numbers around inside a square root.

sqrt(20)/sqrt(8)=(sqrt(10)*sqrt(2))/(sqrt(2)*sqrt(4))

Write that out and see if it helps you.

I ended up getting 10^1/2 / 2 as R which gave me D as well.

You can always check by multiplying 8 by r^2. If that works it has to be right.

I figured R^2 to be 20/8 (before simplifying to 10/4) so...

It’s just to check if you made an algebra mistake. It looks to me like it has to be D though.

Yeah it looks like it...I’ve gone through it a few different ways...

Tyreaus Dreacon wrote:

daledude wrote: I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I thought it was (x+4)^2 = (5x+2)(x-2) is what I got...

Are you sure those (x+4)'s don’t cancel?

I’m determined to live forever, or die trying. - Yossarian

*14 year old reads topic*

LOL WTF
I NOES HAO 2 MULTIPLY

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I thought it was (x+4)^2 = (5x+2)(x-2) is what I got...

Are you sure those (x+4)'s don’t cancel?

Doesn’t make sense they would. If you have
(5x+2)/(x+4) = (x+4)/(x-2)
You’d need to multiply both sides by (x+4) and (x-2) to get rid of them on each side...
I think. o.o

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I thought it was (x 4)^2 = (5x 2)(x-2) is what I got...

Are you sure those (x 4)'s don’t cancel?

Doesn’t make sense they would. If you have
(5x 2)/(x 4) = (x 4)/(x-2)
You’d need to multiply both sides by (x 4) and (x-2) to get rid of them on each side...
I think. o.o

Oh wait. I fucked up. There’s an = there not an * doh!

I’m determined to live forever, or die trying. - Yossarian

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote:

Tyreaus Dreacon wrote:

daledude wrote: I think I messed something up with 14. The roots aren’t in the right spots. I think I’m approaching it in the right way though. Maybe try working it out from the beginning again...

I thought it was (x 4)^2 = (5x 2)(x-2) is what I got...

Are you sure those (x 4)'s don’t cancel?

Doesn’t make sense they would. If you have
(5x 2)/(x 4) = (x 4)/(x-2)
You’d need to multiply both sides by (x 4) and (x-2) to get rid of them on each side...
I think. o.o

Oh wait. I fucked up. There’s an = there not an * doh!

lol, yeah and I got some confusing thing like, 5 and -2 or something stupid...