See if you can figure these out

Questions extracted from my Exercise Book - A.J. Sadler 2C:

If an object is dropped, the distance it has fallen t seconds later is d metres where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft?
b) How far did the stone fall in the first second?
c) How far did the stone fall in the second second?
d) How far did the stone fall in the third second?
e) Is the relationship between t and d a linear one?
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)?

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)?

Shit!I am having a math overload here!

If one airplane leaves Chicago at 2:00 pm and another leaves Los Angeles at 5:00 am, what is the price of apples in Miami?

I have a gray, cotton sweatshirt. What are the names of my cats?

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

Voyager wrote:

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

If not Depression, then Fuzzy.

NeonMan5 wrote: Questions extracted from my Exercise Book - A.J. Sadler 2C:

If an object is dropped, the distance it has fallen t seconds later is d metres where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft?
b) How far did the stone fall in the first second?
c) How far did the stone fall in the second second?
d) How far did the stone fall in the third second?
e) Is the relationship between t and d a linear one?
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)?

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)?

A)24.5 meters
4.9 meters
C)9.8 meters
D)14.7 meters
E)Yes
F)2.5 seconds

G)8 seconds. Or its a trick question cause the roof is flat and its covered by solar panels so a tile couldnt fall....or am I just over analyzing it?

Voyager wrote:

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

Huh? Im not an emo peice of shit. There names are Speedy(Named when I was 7), Stoney(My little brother named this one), and Boo(I leik Boo).

Saosin wrote:

NeonMan5 wrote: Questions extracted from my Exercise Book - A.J. Sadler 2C:

If an object is dropped, the distance it has fallen t seconds later is d metres where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft?
b) How far did the stone fall in the first second?
c) How far did the stone fall in the second second?
d) How far did the stone fall in the third second?
e) Is the relationship between t and d a linear one?
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)?

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)?

A)24.5 meters
4.9 meters
C)9.8 meters
D)14.7 meters
E)Yes
F)2.5 seconds

G)8 seconds. Or its a trick question cause the roof is flat and its covered by solar panels so a tile couldnt fall....or am I just over analyzing it?

Are you including the moons gravity in your anser?

King Boo wrote:

Voyager wrote:

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

Huh? Im not an emo peice of shit. There names are Speedy(Named when I was 7), Stoney(My little brother named this one), and Boo(I leik Boo).

I’m sorry Your Highness, where did I refer to you as “an emo piece of shit”?

Voyager wrote:

Saosin wrote:

NeonMan5 wrote: Questions extracted from my Exercise Book - A.J. Sadler 2C:

If an object is dropped, the distance it has fallen t seconds later is d metres where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft?
b) How far did the stone fall in the first second?
c) How far did the stone fall in the second second?
d) How far did the stone fall in the third second?
e) Is the relationship between t and d a linear one?
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)?

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)?

A)24.5 meters
4.9 meters
C)9.8 meters
D)14.7 meters
E)Yes
F)2.5 seconds

G)8 seconds. Or its a trick question cause the roof is flat and its covered by solar panels so a tile couldnt fall....or am I just over analyzing it?

Are you including the moons gravity in your anser?

Im including the information he has given me. Im assuming the moons gravity is already given in the question too.

Voyager wrote:

King Boo wrote:

Voyager wrote:

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

Huh? Im not an emo peice of shit. There names are Speedy(Named when I was 7), Stoney(My little brother named this one), and Boo(I leik Boo).

I’m sorry Your Highness, where did I refer to you as “an emo piece of shit”?

You said my cats were shadow ad depression. Thats what someone like Arch angel would name there cats.

King Boo wrote:

Voyager wrote:

King Boo wrote:

Voyager wrote:

King Boo wrote: I have a gray, cotton sweatshirt. What are the names of my cats?

Easy, Shadow and Depression.

Huh? Im not an emo peice of shit. There names are Speedy(Named when I was 7), Stoney(My little brother named this one), and Boo(I leik Boo).

I’m sorry Your Highness, where did I refer to you as “an emo piece of shit”?

You said my cats were shadow ad depression. Thats what someone like Arch angel would name there cats.

shadow is a normal name but depression ya i see what you mean.

Saosin wrote:

NeonMan5 wrote: Questions extracted from my Exercise Book - A.J. Sadler 2C:

If an object is dropped, the distance it has fallen t seconds later is d metres where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft?
b) How far did the stone fall in the first second?
c) How far did the stone fall in the second second?
d) How far did the stone fall in the third second?
e) Is the relationship between t and d a linear one?
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)?

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)?

A)24.5 meters - Incorrect
4.9 meters - Correct
C)9.8 meters - Incorrect
D)14.7 meters - Incorrect
E)Yes - Incorrect (but I’m not sure why)
F)2.5 seconds - Incorrect

G)8 seconds. Or its a trick question cause the roof is flat and its covered by solar panels so a tile couldnt fall....or am I just over analyzing it? - Incorrect, and it is not a trick question

If you want me to pm the answers just ask.

*sigh* retards.

If an object is dropped, the distance it has fallen t seconds later is d meters where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft? 5*5*4.9 = 122.5 meters.
b) How far did the stone fall in the first second? 1*1*4.9 = 4.9 Meters
c) How far did the stone fall in the second second? 2*2*4.9 = 19.6 Meters is the TOTAL - 4.9 Meters (first second) = 14.7 Meters if you start at the end of the first second and end at the end of second second.
d) How far did the stone fall in the third second? 3*3*4.9 = 44.1 Meters - 19.6 Meters (first and second seconds) = 24.5 Meters if you start at the end of the second second and end at the end of the third second.
e) Is the relationship between t and d a linear one? No, it is parabolic.
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)? 61.25 = 4.9 * t^2
12.5 = t^2
3.535... = t
t = 3.5

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)? 10 = .8*t^2
12.5 = t^2
3.535 = t
3.5 = t

Funny, Question G is actually Question F but with everything divided by 6.125

Hope you got a good grade.

THE KING HAS RETURNED!

derdev789 wrote: *sigh* retards.

If an object is dropped, the distance it has fallen t seconds later is d meters where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft? 5*5*4.9 = 122.5 meters.
b) How far did the stone fall in the first second? 1*1*4.9 = 4.9 Meters
c) How far did the stone fall in the second second? 2*2*4.9 = 19.6 Meters is the TOTAL - 4.9 Meters (first second) = 14.7 Meters if you start at the end of the first second and end at the end of second second.
d) How far did the stone fall in the third second? 3*3*4.9 = 44.1 Meters - 19.6 Meters (first and second seconds) = 24.5 Meters if you start at the end of the second second and end at the end of the third second.
e) Is the relationship between t and d a linear one? No, it is parabolic.
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)? 61.25 = 4.9 * t^2
12.5 = t^2
3.535... = t
t = 3.5

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)? 10 = .8*t^2
12.5 = t^2
3.535 = t
3.5 = t

Funny, Question G is actually Question F but with everything divided by 6.125

Hope you got a good grade.
CORRECT!

Well done. At least somebody knows their math.

Yeah, I get good grades, but this was just some work set for us over the easter holidays.

NeonMan5 wrote:

derdev789 wrote: *sigh* retards.

If an object is dropped, the distance it has fallen t seconds later is d meters where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft? 5*5*4.9 = 122.5 meters.
b) How far did the stone fall in the first second? 1*1*4.9 = 4.9 Meters
c) How far did the stone fall in the second second? 2*2*4.9 = 19.6 Meters is the TOTAL - 4.9 Meters (first second) = 14.7 Meters if you start at the end of the first second and end at the end of second second.
d) How far did the stone fall in the third second? 3*3*4.9 = 44.1 Meters - 19.6 Meters (first and second seconds) = 24.5 Meters if you start at the end of the second second and end at the end of the third second.
e) Is the relationship between t and d a linear one? No, it is parabolic.
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)? 61.25 = 4.9 * t^2
12.5 = t^2
3.535... = t
t = 3.5

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)? 10 = .8*t^2
12.5 = t^2
3.535 = t
3.5 = t

Funny, Question G is actually Question F but with everything divided by 6.125

Hope you got a good grade.
CORRECT!

Well done. At least somebody knows their math.

Yeah, I get good grades, but this was just some work set for us over the easter holidays.

Pretty easy homework. You got lucky.

THE KING HAS RETURNED!

NeonMan5 wrote:

derdev789 wrote: *sigh* retards.

If an object is dropped, the distance it has fallen t seconds later is d meters where d is given by:
d=4.9t(squared)

A stone is dropped down an old mine shaft and hits the bottom at 5 seconds later.

a) How deep is the mine shaft? 5*5*4.9 = 122.5 meters.
b) How far did the stone fall in the first second? 1*1*4.9 = 4.9 Meters
c) How far did the stone fall in the second second? 2*2*4.9 = 19.6 Meters is the TOTAL - 4.9 Meters (first second) = 14.7 Meters if you start at the end of the first second and end at the end of second second.
d) How far did the stone fall in the third second? 3*3*4.9 = 44.1 Meters - 19.6 Meters (first and second seconds) = 24.5 Meters if you start at the end of the second second and end at the end of the third second.
e) Is the relationship between t and d a linear one? No, it is parabolic.
f) If the mine shaft had only been half as deep how long would it have taken the stone to reach the bottom (to 1 d.p.)? 61.25 = 4.9 * t^2
12.5 = t^2
3.535... = t
t = 3.5

g) When something is dropped on the moon the distance fallen t seconds later is d metres where d=0.8t(squared)

Plans for a proposed scientific base on the moon show a structure that is to be ten metres high with solar panels on the flat roof. If a tile falls from the roof how long will take to reach the surface of the moon (to 1 d.p.)? 10 = .8*t^2
12.5 = t^2
3.535 = t
3.5 = t

Funny, Question G is actually Question F but with everything divided by 6.125

Hope you got a good grade.
CORRECT!

Well done. At least somebody knows their math.

Yeah, I get good grades, but this was just some work set for us over the easter holidays.

Damn this stuff is hard.But hen again I’m so bad at math I practically have trouble factoring.